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Audio and Video Talk
General Discussion
Audio 101 - Can your speaker be too big for your amp???
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<blockquote data-quote="Ampdog" data-source="post: 60339" data-attributes="member: 144"><p>Goneten (re your post #9),</p><p></p><p>Respecting your knowledge in this field and particularly your experience (totally overshadowing mine), I can nevertheless not see the almost watertight differences you seem to draw. Yes, it is obviously clear (as I also stated) that sensitivity and efficiency are calculated in different ways; the one is after all given in dB and the other as a ratio! But both is dependant on the varying impedance - both are average values integrated over a frequency band, both vary in the same manner, and when talking about relative differences between loudspeakers, they indicate the same tendencies: doubling the efficiency gives a 3dB rise in sensitivity and vice versa. You mention mathematics; perhaps one could cut qualitative statements short by looking at the simple conversion factor between the two:</p><p></p><p><span style="color: blue">Sensitivity(dB) = 112 + 10*log(efficiency)</span></p><p></p><p>That is a direct relationship without other variables. If you disagree with that you must kindly give us your relationship if any.</p><p></p><p>Further:</p><p></p><p></p><p>Again, that was not the point. One cannot explain the existence of dc or lack of it using watts - there are no negative watts. I merely tried to indicate that a square wave (50% m.s. ratio as will result from symmetrical clipping) does not necessarily involve a nett d.c. or damaging excursion as some believe, since it contains the element of frequency which dc does not.</p><p></p><p>[I would suggest that a new thread be opened if further discussion is desired.]</p></blockquote><p></p>
[QUOTE="Ampdog, post: 60339, member: 144"] Goneten (re your post #9), Respecting your knowledge in this field and particularly your experience (totally overshadowing mine), I can nevertheless not see the almost watertight differences you seem to draw. Yes, it is obviously clear (as I also stated) that sensitivity and efficiency are calculated in different ways; the one is after all given in dB and the other as a ratio! But both is dependant on the varying impedance - both are average values integrated over a frequency band, both vary in the same manner, and when talking about relative differences between loudspeakers, they indicate the same tendencies: doubling the efficiency gives a 3dB rise in sensitivity and vice versa. You mention mathematics; perhaps one could cut qualitative statements short by looking at the simple conversion factor between the two: [color=blue]Sensitivity(dB) = 112 + 10*log(efficiency)[/color] That is a direct relationship without other variables. If you disagree with that you must kindly give us your relationship if any. Further: Again, that was not the point. One cannot explain the existence of dc or lack of it using watts - there are no negative watts. I merely tried to indicate that a square wave (50% m.s. ratio as will result from symmetrical clipping) does not necessarily involve a nett d.c. or damaging excursion as some believe, since it contains the element of frequency which dc does not. [I would suggest that a new thread be opened if further discussion is desired.] [/QUOTE]
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Audio and Video Talk
General Discussion
Audio 101 - Can your speaker be too big for your amp???
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